4x^2-3x=(16x-12)/x

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Solution for 4x^2-3x=(16x-12)/x equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

4*x^2-(3*x) = (16*x-12)/x // - (16*x-12)/x

4*x^2-((16*x-12)/x)-(3*x) = 0

4*x^2-((16*x-12)/x)-3*x = 0

(-1*(16*x-12))/x+4*x^2-3*x = 0

(-1*(16*x-12))/x+(4*x*x^2)/x+(-3*x*x)/x = 0

4*x*x^2-1*(16*x-12)-3*x*x = 0

4*x^3-3*x^2-16*x+12 = 0

4*x^3-3*x^2-16*x+12 = 0

4*x^3-3*x^2-16*x+12 = 0

{ 1, -1, 2, -2, 3, -3, 4, -4, 6, -6, 12, -12 }

1

x = 1

4*x^3-3*x^2-16*x+12 = -3

1

-1

x = -1

4*x^3-3*x^2-16*x+12 = 21

-1

2

x = 2

4*x^3-3*x^2-16*x+12 = 0

2

x-2

4*x^2+5*x-6

4*x^3-3*x^2-16*x+12

x-2

8*x^2-4*x^3

5*x^2-16*x+12

10*x-5*x^2

12-6*x

6*x-12

0

4*x^2+5*x-6 = 0

DELTA = 5^2-(-6*4*4)

DELTA = 121

DELTA > 0

x = (121^(1/2)-5)/(2*4) or x = (-121^(1/2)-5)/(2*4)

x = 3/4 or x = -2

x in { -2, 3/4, 2}

(x+2)*(x-3/4)*(x-2) = 0

((x+2)*(x-3/4)*(x-2))/x = 0

((x+2)*(x-3/4)*(x-2))/x = 0 // * x

(x+2)*(x-3/4)*(x-2) = 0

( x+2 )

x+2 = 0 // - 2

x = -2

( x-2 )

x-2 = 0 // + 2

x = 2

( x-3/4 )

x-3/4 = 0 // + 3/4

x = 3/4

x in { -2, 2, 3/4 }

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